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Simple Leap Year Checker in JavaScript

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Submitted on: 3/30/2016 11:07:22 PM
By: Jake R. Pomperada  
Level: Beginner
User Rating: Unrated
Compatibility: JavaScript
Views: 1773
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     Here is a very simple leaper year checker that I wrote using JavaScipt as my programming language. The code is very ideal for beginners in JavaScript Programming. If you have some questions please send me an email at jakerpomperada@gmail.com and jakerpomperada@yahoo.com. Add me at Facebook my address is jakerpomperada@gmail.com and jakerpomperada@yahoo.com My mobile number here in the Philippines is 09173084360.
 
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'**************************************
' Name: Simple Leap Year Checker in JavaScript
' Description:Here is a very simple leaper year checker that I wrote using JavaScipt as my programming language. The code is very ideal for beginners in JavaScript Programming.
If you have some questions please send me an email at jakerpomperada@gmail.com and jakerpomperada@yahoo.com.
Add me at Facebook my address is jakerpomperada@gmail.com and jakerpomperada@yahoo.com
My mobile number here in the Philippines is 09173084360.
' By: Jake R. Pomperada
'**************************************

<html>
<head>
 <title>Simple Leap Year Checker in JavaScript </title>
<h1> Simple Leap Year Checker in JavaScript </h1>
<br>
 <script language = "JavaScript">
 x=1900;
	str=x+" is a ";
	str1="";
	if (x%400==0)
	 str1="leap year";
	else if (x%4==0 && x%100!=0)
	 str1="leap year";
	else
	 str1="not a leap year";
	document.write(str+str1);
 </script>
</head>
</html>


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